A saturated clay specimen has a water content of 40% and a specific gravity of solids of 2.70. The saturated unit weight of the specimen is most nearly:
- (A)8.0 kN/m³
- (B)12.7 kN/m³
- (C)17.8 kN/m³
- (D)24.3 kN/m³
Show worked solution
Answer: (C)
Saturation forces e = wG_s = 1.08, and the phase relation returns γ_sat = 17.8 kN/m³.
Saturation () fixes the void ratio through .
With known, the unit weight follows directly, taking kN/m³.
FE Reference Handbook — Geotechnical: Phase Relationships (Unit Weight Equations)
Why the other choices appear
- (A)Reports the buoyant (submerged) unit weight, 17.83 − 9.81 = 8.0 kN/m³, instead of the saturated unit weight.
- (B)Reports the dry unit weight, G_s·γ_w/(1+e) = 12.7 kN/m³, omitting the pore water.
- (D)Computes the void ratio as e = w/G_s = 0.148, giving (2.70 + 0.148)(9.81)/1.148 = 24.3 kN/m³.